algebra can you help me with # 2 and # 3 thanks

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algebra can you help me with # 2 and # 3 thanks

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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the cooking one?
yes please

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cook has 4 quarts that is 50% chicken stock. so at the moment it is 50% of 4 = 2 quarts chicken stock. so for example if she adds 3 quarts of chicken stock she will have 4+3= 7 quarts of liquid of which 2 + 3 = 5 quarts is chicken stock, and the percent will be 5/7 * 100. this is not what you want obviously, i am just trying to explain where the equation will come from. if she adds x quarts of chicken stock she will have 2+x quarts of chicken stock and 4+x quarts of liquid. you want \[\frac{2+x}{4+x}=.75\] \[2+x=.75(4+x)\] last equation says your two quarts of chicken stock plus your x quarts must be 75% of the total liquid. now we solve multiply out \[x+2=.75x+.75\times 4= .75x+3\] \[.25x=1\] subtract .75x from both sides and subtract 2 from both sides \[x=\frac{1}{.25}=\frac{100}{25}=4\]
and #3 thanks
ok #3 looks like the previous one we did so let me be careful and not put the 1 on the wrong side like i did last time.
keep seeming to put the 1 on the wrong side. you have two rates, r and r +1 \[\frac{12}{r}=\frac{12}{r+1}+1\] slower person's time is one less more than faster persons. \[\frac{12}{r}=\frac{12+r+1}{r+1}=\frac{r+13}{r+1}\] cross multiply\[12(r+1)=r(r+13)\] \[12r+12=r^2+13r\] \[r^2+r-12=0\] \[(r+4)(r-3)=0\] \[r=3\] \[r=-4\] so r = 3

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