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anonymous
 5 years ago
hey guys a question in physics,
the angular momentum of the earth revolving around the sun is proportional to R^n where R is the distance between the earth and the sun. the value of n is?
anonymous
 5 years ago
hey guys a question in physics, the angular momentum of the earth revolving around the sun is proportional to R^n where R is the distance between the earth and the sun. the value of n is?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0v=2pi*R/(365*24*3600)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what i thought...but unfortunately my book says it 1/2. i dont know how!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[R^{2}{} (2 \pi)\over(365*24*3600)*\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the value of n should be 2 ryt?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.livephysics.com/problemsandanswers/classicalmechanics/findearthangularmomentum.html here its solved the same way, so i think its plausible to go with 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0When I was taking physics I found this site very useful www.physicsfourm.com

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you miss an "s" by any chance?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01/2 is actually correct. I'll prove it for you: L = m (r x v), which means that L = mrv (because in this case, our angle is 90) Now, we know that F (gravity) = GMm/r^2 and that F = ma assuming uniform circular motion, a = v^2/r, which means that v^2 = GM/r^3 Plugging this back into our angular momentum equation, we get \[L = mr^2*\sqrt{GM}*r^{1.5} = m*\sqrt{GM} * r ^.5\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey how did you get this, v^2 = GM/r^3 ?? m totally clueless.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0mv^2/r=GM/r^2 =>v^2=GM/r plugn ds in ang. momntm eq.  L=mvr=mr(GM/r)^(1/2)=m(GMr)^(1/2) so n should be 1/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have a question, why wouldnt replacing v by \[\omega r\] work??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It does work, you just need to do an extra step to convert a= v^2/r to w^2r

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you work it out. i am not able to comprehend. :(
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