A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing
anonymous
 5 years ago
If an object is thrown upward with an initial velocity of 10 ft per
second, then its height is given by h = 10t2 + 40t. What is its maximum height?
anonymous
 5 years ago
If an object is thrown upward with an initial velocity of 10 ft per second, then its height is given by h = 10t2 + 40t. What is its maximum height?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0differentiating gives h'= 20t+40 setting equal to 0 you can find the min/max of the function. 20t+40=0 implies t =2 and it is clearly a maximum
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.