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amistre64

  • 5 years ago

does \[\frac{1}{1-2x}=2^n\]?

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  1. anonymous
    • 5 years ago
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    not if x = 3!

  2. amistre64
    • 5 years ago
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    what are the steps to get it from the left to the right?

  3. amistre64
    • 5 years ago
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    apparently discrete math is my achilles heel lol

  4. anonymous
    • 5 years ago
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    this question honestly does not make any sense. you have an x on one side and n on the other.

  5. anonymous
    • 5 years ago
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    ^^I agree.

  6. amistre64
    • 5 years ago
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    hmmm..... well, i think i write it right..

  7. amistre64
    • 5 years ago
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    should there be an 'n' up top instead of a 1?

  8. anonymous
    • 5 years ago
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    Then I think they are not equal.

  9. anonymous
    • 5 years ago
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    ooooooooooooohhhhhhhhh i bet i see what this should be. maybe. \[\frac{1}{1-x}=\Sigma x^n\] for -1<x<1 now if we replace x by 2x we get \[\frac{1}{1-2x}=\Sigma (2x)^n = \Sigma 2^nx^n\] for \[-\frac{1}{2}<x<\frac{1}{2}\] perhaps this is what you had in mind?

  10. amistre64
    • 5 years ago
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    that looks more like it :)

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spraguer (Moderator)
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