## anonymous 5 years ago how would i go about solving 8e^2x=20

1. anonymous

natural log cancels the e. Then solve normally.

2. anonymous

divide by 8, take the log, divide by 2

3. anonymous

Like 8/20 first. Then ln e^2x, and you get 2x=ln(20/8). Then you divide all tht by 2 and that's the answer.

4. anonymous

I mean 20/8

5. anonymous

$8e ^{2x} = 20$ $\ln (20/8) = 2x$ $x= .5*\ln(20/8) = \ln(\sqrt{2.5})$

6. anonymous

thank youuuuuuuu