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anonymous
 5 years ago
how would i go about solving 8e^2x=20. btw we are on logs.
anonymous
 5 years ago
how would i go about solving 8e^2x=20. btw we are on logs.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0e^2x=20/8 lne^2x = ln (20/8) 2x = ln (20/8) x = [ln(20/80]/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[8e^{2x}=20\] \[e^{2x}=4\]\[2x=ln(4)\] \[x=\frac{ln(4)}{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and since \[ln(4) = ln(2^2)=2ln(2)\] \[\frac{ln(4)}{2}=ln(2)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0time for me to retire

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or whatever \[\frac{20}{8}\] is

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0they already answer it in the other question box :D

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hope they didn't write \[\frac{ln(4)}{2}\]!
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