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anonymous
 5 years ago
4x2  8x + 5y2 + 30y  41 = 0
A) The graph is the point (1, 3).
B) The graph is an ellipse with center (1, 3).
C) The graph is a circle with center (1, 3).
D) The equation has no graph.
anonymous
 5 years ago
4x2  8x + 5y2 + 30y  41 = 0 A) The graph is the point (1, 3). B) The graph is an ellipse with center (1, 3). C) The graph is a circle with center (1, 3). D) The equation has no graph.

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1it is definitely not a circle since we have the coefficients of x^2 and y^2 do not equal it is likely to be an ellipse since the sign of x^2 is the same as the sign of y^2, but there could also be no graph now we are required to do more thinking

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1i will eat and if someone else hasnt answer i will look at is some more k?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1hey try to write it like this [(x1)^2]/5+[(y+3)^2]/4=9/2 this an ellsipse since the RHS is not negative

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1also if the RHS was zero after writing it in that form this would the graph of the point (1,3)
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