## anonymous 5 years ago Definite integral this time: from [1,-2] 1-2x+3d^2 dx Integral I get is: x-x^2+x^3 Evaluate at 1 for ... 1 Evaluate at -2 for ....-14 1-(-14)=1+14=15.....oh that is the right answer...dang double negatives....nevermind bonus question though...why isnt the equation editor thing available for the question or is it but I don't know how to access it?

1. amistre64

3d^2 ?

2. amistre64

double integral right?

3. amistre64

gotta type like this '\' [\stuff in here\], without the '' parts: $\sin(32)^2 + \frac{x}{x} - int_{1}^{4}(x)dx$

4. amistre64

gotta put some spurious \\\\ s in it lol

5. anonymous

Okies I'll try putting in some slashies when my final isnt tomorrow =)