Definite integral this time: from [1,-2] 1-2x+3d^2 dx Integral I get is: x-x^2+x^3 Evaluate at 1 for ... 1 Evaluate at -2 for ....-14 1-(-14)=1+14=15.....oh that is the right answer...dang double negatives....nevermind bonus question though...why isnt the equation editor thing available for the question or is it but I don't know how to access it?

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Definite integral this time: from [1,-2] 1-2x+3d^2 dx Integral I get is: x-x^2+x^3 Evaluate at 1 for ... 1 Evaluate at -2 for ....-14 1-(-14)=1+14=15.....oh that is the right answer...dang double negatives....nevermind bonus question though...why isnt the equation editor thing available for the question or is it but I don't know how to access it?

Mathematics
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3d^2 ?
double integral right?
gotta type like this '\' [\stuff in here\], without the '' parts: \[\sin(32)^2 + \frac{x}{x} - int_{1}^{4}(x)dx\]

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gotta put some spurious \\\\ s in it lol
Okies I'll try putting in some slashies when my final isnt tomorrow =)

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