anonymous
  • anonymous
can someone help me find the absolute and local extrema in this equation (3x-4)/(x^2+1)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
sure
amistre64
  • amistre64
(x^2+1)(3) - (3x-4)(2x) = 0
anonymous
  • anonymous
on the intervals [-2,2]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

amistre64
  • amistre64
3x^2 +3 -6x^2 +8x = 0 -3x^2 +3 +8x = 0 0 = 3x^2 -8x -3
amistre64
  • amistre64
(x-3) (x+ 1/3) = x = x and x = -1/3 are the max and min
amistre64
  • amistre64
x = 3 and x = -1/3......
amistre64
  • amistre64
f(-2) = ? f(-1/3) = ? f(2) = ?
anonymous
  • anonymous
so what do u do with the denominator
amistre64
  • amistre64
nothing; the top directs the =0 part; not the bottom
amistre64
  • amistre64
put these x values into the original equationand determine which is higher
anonymous
  • anonymous
awesome thanks a lot man the denominator was throwing me off
amistre64
  • amistre64
there is no vertical asypmtote; so you aint gotta worry about bad values :)
myininaya
  • myininaya
also x^2+1=0 has no real solution so this does not give you a critcal number anyways
myininaya
  • myininaya
right what amistre said no vertical asym
anonymous
  • anonymous
awesome thanks a lot guys

Looking for something else?

Not the answer you are looking for? Search for more explanations.