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anonymous

  • 5 years ago

can someone help me evaluate the limit of this equation limit approaches 0(e^(4x) - 1-4x)/(x^2)

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  1. anonymous
    • 5 years ago
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    0

  2. anonymous
    • 5 years ago
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    i get zero over zero

  3. amistre64
    • 5 years ago
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    derive top and bottom seperately; then limit them seperately

  4. amistre64
    • 5 years ago
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    lhopitals rule

  5. amistre64
    • 5 years ago
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    i wonder if you can do that more than once

  6. anonymous
    • 5 years ago
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    Yes. You can do it as long as both the denominator and numerator have 0/0 or ∞/∞

  7. amistre64
    • 5 years ago
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    2x doesnt seem to help does it lol

  8. amistre64
    • 5 years ago
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    you can? over and over?

  9. anonymous
    • 5 years ago
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    yeah as long as you get 0/0 or infin/infin

  10. amistre64
    • 5 years ago
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    i thought i read that somewhere lol

  11. anonymous
    • 5 years ago
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    ok so i would get the derivative of the top correct over the derivative of the bottom

  12. amistre64
    • 5 years ago
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    yes

  13. amistre64
    • 5 years ago
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    4.e^4x - 4 2.e^4x - 2 ---------- = --------- 2x x

  14. amistre64
    • 5 years ago
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    8.e^4x at 0 = ...8 right?

  15. anonymous
    • 5 years ago
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    yeah thats what the answer sheet got but i still dont understand how you got it

  16. amistre64
    • 5 years ago
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    x^2; 2x ; 2 tese are the derivatives right? of the bottom

  17. anonymous
    • 5 years ago
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    yeah

  18. amistre64
    • 5 years ago
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    e^4x -1 - 4x; 4.e^4x -4; 16.e^4x for the top

  19. amistre64
    • 5 years ago
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    16.e^4x ------- = 8.e^4x ; at x=0; 8.1 = 8 2

  20. anonymous
    • 5 years ago
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    cant see where you get the 16 from sorry

  21. amistre64
    • 5 years ago
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    4.e^4x right? derive e^4x again and we get: 4. 4.e^4x = 16.e^4x

  22. amistre64
    • 5 years ago
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    e^u derives to : Du e^u

  23. anonymous
    • 5 years ago
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    ok so u used l hopital twice

  24. amistre64
    • 5 years ago
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    yes lol

  25. anonymous
    • 5 years ago
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    ok ok awesome and we were just talking about that

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