anonymous
  • anonymous
if angle 1 = 50 degrees and angle DAB = 35 degrees, find arc AC and m of angle ABC
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
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anonymous
  • anonymous
I do know whatever arc AC is will be the same for angle ABC
anonymous
  • anonymous
If I add 35 + 50 = 85/2 = 42.5???

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anonymous
  • anonymous
Yes this one.
watchmath
  • watchmath
Do we know if BC passes through the origin?
watchmath
  • watchmath
I mean the center
anonymous
  • anonymous
it doesnt show a center. because E is definitely not in the center
anonymous
  • anonymous
But yes BC passes through E and so does AD
watchmath
  • watchmath
Ok first let's find \(\angle ABC\)
anonymous
  • anonymous
when I use the formula when two cords of a circle intersect, the measure of each angle formed is one-half the sum of the measures of its intercepted arc and the arc intercepted by its vertical angle.
anonymous
  • anonymous
I get that 42.4 number a degree can not be that
watchmath
  • watchmath
Note that we can find angle AEB. Then you can find angle ABC.
anonymous
  • anonymous
180-50 = 130
watchmath
  • watchmath
Good! so now what is the angle of ABC?
anonymous
  • anonymous
180- 130 = 50 no?
anonymous
  • anonymous
its too small to be 50
watchmath
  • watchmath
Sorry... AEB = 180 - angle 1 = 180 -50 = 130.
anonymous
  • anonymous
ok so Angle AEB is 130 and we know angle A is 35 add those and subtract 180 gets me 15 degrees?
watchmath
  • watchmath
Great! :)
anonymous
  • anonymous
So if angle ABC is 15 degrees then the arc AC is 15
watchmath
  • watchmath
Are we looking for the length of the arc AC or the angle measure of the arc AC ?
anonymous
  • anonymous
the measure of arc AC and the measure of angle ABC
watchmath
  • watchmath
Ok, the 15 is the inscribed angle of AC, so the central angle is twice of that, which is 30.
anonymous
  • anonymous
ok... this is because the angle of ABC is inside a triangle right...
watchmath
  • watchmath
yes
anonymous
  • anonymous
thank you
watchmath
  • watchmath
If I am not around and you have a question you can ask me here: http://www.ask.watchmath.com :D
anonymous
  • anonymous
oh thank you!

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