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I do know whatever arc AC is will be the same for angle ABC
If I add 35 + 50 = 85/2 = 42.5???
Yes this one.
Do we know if BC passes through the origin?
I mean the center
it doesnt show a center. because E is definitely not in the center
But yes BC passes through E and so does AD
Ok first let's find \(\angle ABC\)
when I use the formula when two cords of a circle intersect, the measure of each angle formed is one-half the sum of the measures of its intercepted arc and the arc intercepted by its vertical angle.
I get that 42.4 number a degree can not be that
Note that we can find angle AEB. Then you can find angle ABC.
180-50 = 130
Good! so now what is the angle of ABC?
180- 130 = 50 no?
its too small to be 50
Sorry... AEB = 180 - angle 1 = 180 -50 = 130.
ok so Angle AEB is 130 and we know angle A is 35 add those and subtract 180 gets me 15 degrees?
So if angle ABC is 15 degrees then the arc AC is 15
Are we looking for the length of the arc AC or the angle measure of the arc AC ?
the measure of arc AC and the measure of angle ABC
Ok, the 15 is the inscribed angle of AC, so the central angle is twice of that, which is 30.
ok... this is because the angle of ABC is inside a triangle right...
If I am not around and you have a question you can ask me here: http://www.ask.watchmath.com :D
oh thank you!