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anonymous

  • 5 years ago

if angle 1 = 50 degrees and angle DAB = 35 degrees, find arc AC and m of angle ABC

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  1. anonymous
    • 5 years ago
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  2. anonymous
    • 5 years ago
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    I do know whatever arc AC is will be the same for angle ABC

  3. anonymous
    • 5 years ago
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    If I add 35 + 50 = 85/2 = 42.5???

  4. anonymous
    • 5 years ago
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    Yes this one.

  5. watchmath
    • 5 years ago
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    Do we know if BC passes through the origin?

  6. watchmath
    • 5 years ago
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    I mean the center

  7. anonymous
    • 5 years ago
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    it doesnt show a center. because E is definitely not in the center

  8. anonymous
    • 5 years ago
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    But yes BC passes through E and so does AD

  9. watchmath
    • 5 years ago
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    Ok first let's find \(\angle ABC\)

  10. anonymous
    • 5 years ago
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    when I use the formula when two cords of a circle intersect, the measure of each angle formed is one-half the sum of the measures of its intercepted arc and the arc intercepted by its vertical angle.

  11. anonymous
    • 5 years ago
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    I get that 42.4 number a degree can not be that

  12. watchmath
    • 5 years ago
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    Note that we can find angle AEB. Then you can find angle ABC.

  13. anonymous
    • 5 years ago
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    180-50 = 130

  14. watchmath
    • 5 years ago
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    Good! so now what is the angle of ABC?

  15. anonymous
    • 5 years ago
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    180- 130 = 50 no?

  16. anonymous
    • 5 years ago
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    its too small to be 50

  17. watchmath
    • 5 years ago
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    Sorry... AEB = 180 - angle 1 = 180 -50 = 130.

  18. anonymous
    • 5 years ago
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    ok so Angle AEB is 130 and we know angle A is 35 add those and subtract 180 gets me 15 degrees?

  19. watchmath
    • 5 years ago
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    Great! :)

  20. anonymous
    • 5 years ago
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    So if angle ABC is 15 degrees then the arc AC is 15

  21. watchmath
    • 5 years ago
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    Are we looking for the length of the arc AC or the angle measure of the arc AC ?

  22. anonymous
    • 5 years ago
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    the measure of arc AC and the measure of angle ABC

  23. watchmath
    • 5 years ago
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    Ok, the 15 is the inscribed angle of AC, so the central angle is twice of that, which is 30.

  24. anonymous
    • 5 years ago
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    ok... this is because the angle of ABC is inside a triangle right...

  25. watchmath
    • 5 years ago
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    yes

  26. anonymous
    • 5 years ago
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    thank you

  27. watchmath
    • 5 years ago
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    If I am not around and you have a question you can ask me here: http://www.ask.watchmath.com :D

  28. anonymous
    • 5 years ago
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    oh thank you!

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