I need help for my final exam. It is the IB Mathematics SL Paper Two for 2011. First problem. "The following diagram shows triangle ABC. AB = 7cm. BC = 9cm. And Angle ABC = 120 degrees. I need to find AC and the angle BAC.

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I need help for my final exam. It is the IB Mathematics SL Paper Two for 2011. First problem. "The following diagram shows triangle ABC. AB = 7cm. BC = 9cm. And Angle ABC = 120 degrees. I need to find AC and the angle BAC.

Mathematics
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use law of cosines AC = b AB=a BC = c b^2 = a^2 +c^2 - 2ac*cos(120); b= 13.892 then use law of sines: sin(ABC)/b = sin(BAC)/c; sin(120)/13.892 = x/9; x= 0.561040853 arcsin(x) = 34.13 degrees = m BAC
Although this is reasonably straightforward to visualize, could you attach an image? Scan or take a picture of it so we can see what the triangle looks like.
Lol. Or it could get answered lightning fast without that :)

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thanks so much!
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where at?
To the right of his name, where you see the post above.

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