hey someone asked this question earlier, I would like to know how to solve it what is the exact values of y(2) if y'=sin(xy)

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hey someone asked this question earlier, I would like to know how to solve it what is the exact values of y(2) if y'=sin(xy)

Mathematics
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i been stuck on it for the longest time
what does y = cos(xy) derive to?
not that its the answer

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Other answers:

y' = (x'y + xy')-sin(xy) right?
y + x(sin(xy) = 1then maybe
y'=(x'y+xy')(-sin(xy))
lets assune it was -c0s :)
then y + x(sin(xy)) = 1 would be good right?
y = -sin(xy) x +1 ..... dunno if that helps but it might :)
he said: the final answer is suppose to be y(2)=1.632 lets see if that equation holds for his answer
do you know anything about euler's method?
only by name; havent rad to much into it tho
i don't i can do this problem right now my head hurts from trying to find y(2). i
thanks amistre
gets some vittles :)

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