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myininaya

  • 5 years ago

hey someone asked this question earlier, I would like to know how to solve it what is the exact values of y(2) if y'=sin(xy)

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  1. myininaya
    • 5 years ago
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    i been stuck on it for the longest time

  2. amistre64
    • 5 years ago
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    what does y = cos(xy) derive to?

  3. amistre64
    • 5 years ago
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    not that its the answer

  4. amistre64
    • 5 years ago
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    y' = (x'y + xy')-sin(xy) right?

  5. amistre64
    • 5 years ago
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    y + x(sin(xy) = 1then maybe

  6. myininaya
    • 5 years ago
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    y'=(x'y+xy')(-sin(xy))

  7. amistre64
    • 5 years ago
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    lets assune it was -c0s :)

  8. amistre64
    • 5 years ago
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    then y + x(sin(xy)) = 1 would be good right?

  9. amistre64
    • 5 years ago
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    y = -sin(xy) x +1 ..... dunno if that helps but it might :)

  10. myininaya
    • 5 years ago
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    he said: the final answer is suppose to be y(2)=1.632 lets see if that equation holds for his answer

  11. myininaya
    • 5 years ago
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    do you know anything about euler's method?

  12. amistre64
    • 5 years ago
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    only by name; havent rad to much into it tho

  13. myininaya
    • 5 years ago
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    i don't i can do this problem right now my head hurts from trying to find y(2). i

  14. myininaya
    • 5 years ago
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    thanks amistre

  15. amistre64
    • 5 years ago
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    gets some vittles :)

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spraguer (Moderator)
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