• anonymous
Sketch and find the area bounded by: y=-x^2 + 2x + 3 ; y=3 The graph ends up looking like an upside down paraboloid bound at -2 and +2 with a y intercept at (0,7) integrate: -1/3 x^3 + x^2 + 3x @ x=+2 that equals 22/3 @ x=-2 that equals 2/3 22/3 + 2/3 = 24/3 that would be all the area under the curve from [-2,2] = 8 <--but that seems wrong if I went from [0,2] it would be the 22/3 so my thinking is wrong there somewhere. then the other function integrate y=3 = 3x 3x @ 2 = 6 3x @ -2 = -6 6+6=12 subtract the area in the second function from the first function: 22/3 - 36/3 and wrong answer
Mathematics
• Stacey Warren - Expert brainly.com
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SOLVED
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