anonymous 5 years ago PreCal please help! A population of bacteria is growing according to the equation . Estimate when the population will exceed 493. P(t)=400e^(0.05t)

1. anonymous

So I know my equation is 493=400e^(0.05t) but I can't figure out how to solve it

2. anonymous

493 = 400*e^(0.05t) $\ln (493/400) = 0.05t$$t=20*\ln (493/400) = 4.18$

3. anonymous

where did you get 20 from? we haven't learned about natural log yet. I think that's what ln is...

4. anonymous

You are correct, ln is natural log :D It's just a special form of a logarithm with base "e" 1/.05 is 20 :D