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anonymous

  • 5 years ago

I need help with an algebra problem: The perimeter of a rectangle is 158 inches. the length exceeds the width by 57 inches. Find the length and the width.

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  1. anonymous
    • 5 years ago
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    length = width + 57 perimeter = 2*length + 2*width substitute length. p = 2*(width+57) + 2*width = 158. solve for width. substitute width back into first equation.

  2. anonymous
    • 5 years ago
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    So, what is the legth & width?

  3. anonymous
    • 5 years ago
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    p = 2w + 114 + 2w. p = 158. 158 = 4w + 114. 158 - 114 = 4w. 44 / 4 = w = 11. l = w + 57. solve that last one yourself

  4. anonymous
    • 5 years ago
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    Thank you very much :)

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