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anonymous
 5 years ago
The perimeter of a rectangle is 158 inches. The length exceeds the width by 57 inches. Find the length and the width.
anonymous
 5 years ago
The perimeter of a rectangle is 158 inches. The length exceeds the width by 57 inches. Find the length and the width.

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.02l+2w=158 is given in the first sentence

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0l=w+57 is given by second sentence

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0L=length, W=width Then 2L+2W=158. Also L=W+57 Plug in that to the first equation we have 2W+114+2W=158 4W=44 W=11 Hence L=68

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so 2(w+57)+2w=158 2w+2(57)+2w=158 4w+2(57)=158 4w=1582(57)=158114 4w=44 w=44/4=11 so l=11+57=68
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