anonymous
  • anonymous
(2w^7)^3
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
8w^21
anonymous
  • anonymous
(2w^7)(2w^7)(2w^7) exponents are added when multiplied and subtracted when divided. 7+7+7=21
anonymous
  • anonymous
so if i have (6^7)^-2 would my answer be 36^-14

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anonymous
  • anonymous
the negative exponent would make it \[1\div[(6^7)^2] = 1\div(6^7)(6^7) = 1/6^{14}\] To look at another way. But yes you are right, your answer and my answer are the same thing.
anonymous
  • anonymous
No. 6^-14
anonymous
  • anonymous
Do you understand

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