anonymous
  • anonymous
someone wanna help me? x squared = 12 ...solve using square root property?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Take square root of both sides.
anonymous
  • anonymous
so its x=3 rad 2?
anonymous
  • anonymous
What is the square root over the two or the three?

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anonymous
  • anonymous
idk?
anonymous
  • anonymous
That's not a good answer.
anonymous
  • anonymous
idk how to solve this problem? i dont know what the sqauare root of 12 is. all i no is that it is 3 rad 2......what else do i need to do?
anonymous
  • anonymous
You keep the 12 under the radical and break it down: 2.2.3 all under the square root sign.
anonymous
  • anonymous
well...so its not 3 square root of 2?
anonymous
  • anonymous
Right. Actually it is sq rt 4=2
anonymous
  • anonymous
how is it the square root of 4?
anonymous
  • anonymous
sq rt of 12 is equal to sq rt of (4.3)
anonymous
  • anonymous
Not to confuse you, I was just correcting your statement\[2\sqrt{3}\]
anonymous
  • anonymous
so is square root of (x-5) ^ 2 = sqaure root of 2 does x =6?
anonymous
  • anonymous
What?! You lost me.
anonymous
  • anonymous
ok i feel dumb. ok solve this using the square root property x-5 ^ 2 =2
anonymous
  • anonymous
i got 6
anonymous
  • anonymous
Same process: sq rt of both sides.
anonymous
  • anonymous
ok i did and got x-5 = 1
anonymous
  • anonymous
sq rt of 2 is not 1
anonymous
  • anonymous
o...well 2/2 = 1
anonymous
  • anonymous
That is correct, but not part of this problem.
anonymous
  • anonymous
ugh ok so what is the square root of 2?
anonymous
  • anonymous
Sq rt of 2 is sq rt of 2.
anonymous
  • anonymous
but i have to simplyfy ? whats the answer of the equartion then? just x-5 = sqr 2?
anonymous
  • anonymous
You can get a number by using calculator, but since you are studying sq rt you can leave it in that form, same way you left sq rt of 3 in previous problem
anonymous
  • anonymous
do you no how to compelte the square?
anonymous
  • anonymous
Yes, it's that thingy where you divide by 2, then square it
anonymous
  • anonymous
ok x ^ 2 - 8x = 3
anonymous
  • anonymous
slve by completing the squarue
anonymous
  • anonymous
You take that thing in front of x, divide it by 2, square it, add it to each side.
anonymous
  • anonymous
??? can u write it out?
anonymous
  • anonymous
theres nothing infront of x
anonymous
  • anonymous
Looks like -8 to me.
anonymous
  • anonymous
oo yeah i got u
anonymous
  • anonymous
so it would be 16x ^ 2 - 4x = 19?
anonymous
  • anonymous
You did more than my instructions said, the x^2 -8x remains part of the equation, the thing you calculated is added but they are apples and oranges you just write it in.
anonymous
  • anonymous
so how would you write it?
anonymous
  • anonymous
\[x ^{2}-8x+16=3+16\]
anonymous
  • anonymous
ok a couple more.... how would you do 1+5i/3-2i
anonymous
  • anonymous
Have to look up my old notes, been a while.
anonymous
  • anonymous
ok
anonymous
  • anonymous
You have to do conjugation: multiply by (3+2i)/(3+2i)
anonymous
  • anonymous
wait how can u multiply and divide at the same time??
anonymous
  • anonymous
its 2AM...im sorry im sooo tired but this is due at 8AM
anonymous
  • anonymous
You have to manipulate your original problem in order to have something to work with. The choice of conjugation is an off-shoot of the bottom term of your problem. In math you can't change things but you can do tricks, for example if you multiply by 1, you have not changed anything. The thing I told you to multiply is equal to 1.
anonymous
  • anonymous
ok so how do u solve the problem?
anonymous
  • anonymous
You use the FOIL method multiply top The top looks like this (1+5i)(3+2i) The bottom is (3-2i)(3+2i)
anonymous
  • anonymous
i got 13 + 17i
anonymous
  • anonymous
I assume you are working on the top only, recall FOIL method: First, Outside, Inside, Lasts. Be careful to add only like terms, add apples to apples and oranges to oranges.
anonymous
  • anonymous
that what i did cuz u said the bottom = 1
anonymous
  • anonymous
Well, the bottom is not equal to 1, the whole term I introduced is equal to 1. You skip to many steps. Take baby steps, produce the terms of FOIL, eg First is1x3=3
anonymous
  • anonymous
ok .... this is the answer i got..of its wrong just tell me the answer....... 13+17i / 13-12i
anonymous
  • anonymous
You can't get that, my first term is 3
anonymous
  • anonymous
3+ 2i +15i +10i^2 which i^2 = -1 over 9-6i -6 - 4i^2
anonymous
  • anonymous
?
anonymous
  • anonymous
That's it you got rid of some of the i's but there is still one left in top, must check notes again.
anonymous
  • anonymous
ok how do you do 6/cube root of 29?
anonymous
  • anonymous
Not much you can do with that, if you are work with cube roots like you were with square roots.
anonymous
  • anonymous
o snap i wrote that wrong... i meant 6/cube root of 2a ^ 2 sorry!
anonymous
  • anonymous
I am looking over my notes for complex numbers, you are doing everything right; seems the point is to at least get it out of the bottom. Break it down as much you can, final answer would have i in it.
anonymous
  • anonymous
i need that rationalized
anonymous
  • anonymous
For these, they just want you to move square root out of the the bottom. So the same process as complex number, you multiply by\[\sqrt[3]{2a ^{2}}/\sqrt[3]{2a ^{2}}\]
anonymous
  • anonymous
so it would be 6 cube root 2a ^2 over ????
anonymous
  • anonymous
If you multiply cube root of something by cube root of something you would get something. So the answer is whatever is under radical.
anonymous
  • anonymous
2a? is the top right?
anonymous
  • anonymous
2a^2, yes top is right.
anonymous
  • anonymous
ok last problem!! square root of 2x+11 =5
anonymous
  • anonymous
You do the opposite of earlier problems: square both sides.
anonymous
  • anonymous
7?
anonymous
  • anonymous
You skipped to many steps. Jumping in shower.
anonymous
  • anonymous
im going to bed night

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