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anonymous
 5 years ago
I'm lost with 2 different problems and just can't seem to get it. Determine whether the given function f(x) is onetoone. If it is, find its inverse f^1(x), and sketch the graphs of y=f(x) and y=f^1(x) on the same coordinate axes.
(A) f(x) = 1
(B) Let H(x) = 2x^3 + 5x2. Find H^1(2)
anonymous
 5 years ago
I'm lost with 2 different problems and just can't seem to get it. Determine whether the given function f(x) is onetoone. If it is, find its inverse f^1(x), and sketch the graphs of y=f(x) and y=f^1(x) on the same coordinate axes. (A) f(x) = 1 (B) Let H(x) = 2x^3 + 5x2. Find H^1(2)

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0f(x)=1 is not 1 to 1 because it is a constant

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0H(x)=2x^3+5x2 is 1 to 1 if H inverse of (2)=a then H(a)=2 so we have H(a)=2a^3+5a2=2 2a^3+5a2+2=2+2 2a^3+5a=0 a(2a^2+5)=0 a=0

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so H(0)=2 therefore H inverse of (2)=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank so much. How do I sketch these? Any idea?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0you just plug in points

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So, (A) would just be a line right? Straight across on the xaxis?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I do not know which points to graph

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0it would be a horizontal line going through y axis at y=1

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0for B just choose random points on both sides of 0 and including 0
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