Star
  • Star
integrate x(3+x^2)^1/2 between limits of 1 and 0 (x times square root of 3 plus x squared)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[ \int\limits_{0}^{1} x \sqrt{3+x^2} dx\]
anonymous
  • anonymous
right?
Star
  • Star
yes! :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Star
  • Star
i've tried by parts and got 8/3 for first bit but not sure how to work out the second bit
anonymous
  • anonymous
\[(1/2) \int\limits_{o}^{1} (2x)(x+x^2)^{1/2} dx\]
anonymous
  • anonymous
oho there is 3 inplace of first x :)
anonymous
  • anonymous
\[2/3 [(3+x^2)^{3/2}]\]
anonymous
  • anonymous
now u can put the limits
anonymous
  • anonymous
(2/3)(3+1)^(3/2)
anonymous
  • anonymous
(2/3)[(3+1)^(3/2)-(3)^(3/2)]
Star
  • Star
the answer is supposed to be \[8/3 - \sqrt{3}\]
Star
  • Star
but i can't get that answer after i put the limits in
anonymous
  • anonymous
(2/3)[8-3sqrt(3)]
anonymous
  • anonymous
16/3-2sqrt(3) is the answer
anonymous
  • anonymous
is it wrong?
anonymous
  • anonymous
\[\int\limits _0^1x \sqrt{\left(3+x^2\right)}dx = \frac{8}{3}-\sqrt{3} \]

Looking for something else?

Not the answer you are looking for? Search for more explanations.