## anonymous 5 years ago reduce the rational expression to its lowest terms 2x(2)+4x-126/3x(2)-243

"2x(2)" is assumed to be twice x squared. $\frac{2 x^2+4 x-126}{3 x^2-243}=\frac{(2 (-7+x) (9+x))}{(3 (-9+x) (9+x))}=\frac{2 (-7+x)}{3 (-9+x)}$