if jim rides his bike to his office, he averages 12mph. if he drives his car, he averages 36mph. his time is 1/4 hours less then his time bicyling. how far is his office?

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if jim rides his bike to his office, he averages 12mph. if he drives his car, he averages 36mph. his time is 1/4 hours less then his time bicyling. how far is his office?

Mathematics
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can someone help me on this one please :(
So if he drives he takes an X amount of hours to get there and 1/4 X if he bikes.
Woops sorry if he bikes he takes an X amount of time but when he drives he makes 1/4 X of that time.

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so both have something in common when you drive and bike. Do you know what that is?
Well if you cant tell its how far they travel. Regardless if you use a car or a bike you travel a Y amount 1/4 X * 36 = Y X * 12 = Y you can do the rest. Tell me if you are still lost.
ok so do you add like terms?
Umm well want to know how far he travels which is Y but its really hard to do it with that X in there so what you can do is isolate X on each one and substitute
so you will have X = whatever for equation 1 X = whatever for equation 2 and you get whatever for equation 1= whatever for equation 2
ok... lol im sorry im just really bad at these kind of problems
ok isolate X like I said and write it down
so do i multiply w/ -1/4? (the second prob.)
.. i guess im just really confused...

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