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anonymous
 5 years ago
divide
18x^333x^239x9/6x+3
anonymous
 5 years ago
divide 18x^333x^239x9/6x+3

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0First of all notice that three divides both the numerator (the function on top) and the denominator (the other one). This means that you now get this: (6x^311x^213x3)/(2x+1). Now take the term with the highest power in the numerator (6x^3) and divide it by the term with the highest is the denominator (2x) to get 3x^2. Take note of this: you will need it later. Then multiply (2x+1) by (3x^2) and take this product from (6x^311x^2) to get (14x^2). Now add (13x) to this. Divide 14x^2 by 2x to obtain 7x. Note down 7x. Now take (14x7x) from (14x^213x) to get 4x. Divide this by 2x to get 2. Note down 2. The next part is tricky to explian so it might be best if I show your a written calculation using word. Hang on :)
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