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anonymous
 5 years ago
PLEASE HELP
Write cos(t) in terms of csc(t) if the terminal point determined by t is in quadrant II.
anonymous
 5 years ago
PLEASE HELP Write cos(t) in terms of csc(t) if the terminal point determined by t is in quadrant II.

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0csc is in inverted sin; and cos is a shifted sin...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0cos(t) = sin(t+ (pi/2)) csc(t) = 1/sin(t) sooooo..... cos(t) = 1/csc(t+ (pi/2))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0My only options are A. ((csc t)/(sqrt 1 + csc^2t)) B. ((1)/(sqrt 1 + csc^2t)) C.  ((sqrt csc^2t 1)/(csc t)) D. ((1)/(sqrt csc^2t 1)) E. ((1 csc^2t)/(csc t))

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0csc is negative in q2; so d is out

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we can work it backwards as well; pick an angle you know the cos and csc to in Q2 and we what fits :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0cos(120) = 1/2 ; the sin(120) = sqrt(3)/2; csc(120) = 2/sqrt(3)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02 1 *k =  sqrt(3) 2 sqrt(3) k =   4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i cant get a clear picture in my head of what the problem is asking for yet....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0csc(t) = 1/sin(t) \[cos(t) = \sqrt{1\sin^2t}\] \[\cos(t) = \sqrt{11/\csc^2t}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It is in the II quadrant, so C is the option!
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