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anonymous
 5 years ago
find second derivative if (x5)^5+(y2)^5=64
anonymous
 5 years ago
find second derivative if (x5)^5+(y2)^5=64

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0f1{x,y} = 5(x5)^4 f11{x,y} = 20(x5)^3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0f2{x,y} = 5(y2)^4 f22{x,y} = 20(y2)^3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.05(x5)^4 + 5(y2)^4 dy/dx =0 ist derivative

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0right, so long as we imply that y is a function of x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes,, maybe we can let snenlaha do the 2nd derivative hehehehe

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i couldn't continue from the first to the 2nd derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but do you know the process of the ist that i did?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i do and i got it the same as yours

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok try the second so that you cn have confidence in yourself

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do i need to make dy/dx a subject of the formula

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0try to arrange them first, start with dy/dx =

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you can; y' just derives to y''; just be sure to use it as such in its product rule

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes thats the other way doing it,, either one will arrive at the right solution

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0to implicit it again would be easier; no quotient ruls to fight with i believe

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thats rigth....try implicitly ..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.05(x5)^4 + 5(y2)^4 y' =0 20(x5)^3 + 5(y2)^4 y'' + 20(y2)^3 y' y' = 0 then if it works out that way :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Dx(5(x5)^4) + Dx(5(y2)^4 dy/dx) =Dx(0).......ok amistre did it now hehehehe

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i got no idea if its right :)... other than the obvious typos that is 20[(x4)^3 + (y2)^3 y'^2] y'' =  right? 5(y2)^3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.020/5 reduces..... and y' = whatever it equals lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer is suppose to be: y''=(256(X5)^3)/(y2)^9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dy/dx=(x5)^{4}/(y2)^{4}\[d ^{2}y/dx ^{2}=256(x5)^{3}/(y2)^{5}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0it prolly simplifies to that then lol...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah ,... thats the answer to it Snenhlala....try to practice till you arrive to that answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry the denominator for the second derivative should read (y2)^9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you used product rule or quotient rule to find 2nd derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i did mine in quotient rule

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use the quotient rule and sub for dy/dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0mulitply each term by (y2)^4 then factor 4(x5)^3(y2)^3 this will leave (x5)^5+(y2)^4 which equals 64 (from the original equation)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0should read (x5)^5+ (y2)^5 which equals 64

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0should i start to multiply from the 1st derivative or from the origin equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0multiply the second derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y'= (x5)^4 / (y2)^4 4(y2)^4 (x5)^3  4(x5)^4 (y2)^3 y' y"=  now subst. y ' in this equqtion ((y2)^4)^2 4(y2)^4 (x5)^3  4(x5)^4 (y2)^3 [(x5^4)/(y2)^4] y"=  ((y2)^4)^2 4(y2)^4 (x5)^3 + 4(x5)^8 (y2) y"=  (y2)^8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04(y2)^4 (x5)^3 + 4(x5)^8/(y2) y"=  ... sorry its divided by y2 (y2)^8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04(y2)^5 (x5)^3 + 4(x5)^8 y"=  (y2)^9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04 (x5)^3 [(y2)^5 + (x5)^5] y"=  (y2)^9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04 (x5)^3 [64] y"=  (y2)^9 57 seconds ago

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0256 (x5)^3 y"=  (y2)^9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well i think thats it hehehe

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you arrived in the same procedure?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and of course the same answer? lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i did arrive but it too tricky

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah kind of hehehe,,
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