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anonymous
 5 years ago
log (x9) + log x = 1
anonymous
 5 years ago
log (x9) + log x = 1

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radar
 5 years ago
Best ResponseYou've already chosen the best response.0\[10^{x9}+10^{x}=10^{0}\] x9+x=0 2x=9 x=4.5 check:\[10^{4.59}+10^{4.5}=10^{0}=1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow thanks! the way you wrote it made it so much easier to understand ( :

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0log(x^2  9x) = 1 x^2  9x = 10^1 = 10 x^2  9x  10 = 0 (x10)(x+1) = 0 x = 10, 1 ...... log(109) + log(10) = 1 ?? log(1) + 1 = 1 log(1) = 0 10^0 = 1 ... did i do that right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0log(19) = log(10)...1 aint an option tho :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0log(4.5  9) + log(4.5) = 1 log(4.5) + log(4.5) logs cant be negative....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0bases dont add if they aint got the same exponents x^2 + x^3 doesnt equal x^5

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Can not you let them be negative to solve this problem?? lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0well; we will have to write the board of logaritms and enter a plea, then the senate will ahve to vote on it .... its just alot of work for one litle problem :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0base is 10 because it is not given. so all the bases here are the same.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0doesnt matter; bases dont add without like exponents x^2 + x^5 DOESNT EQUAL x^7

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.010^a + 10^b DOESNT EQUAL 10^(a+b)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0logs arent numbers; so they dont work like numbers; they are exponents and follow the rules of exponents

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, I do see the flaw in such an elegant solution, sorry about that justme, please ignore.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so x=4.5 right? seems to work when checked.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0log(x9) + log(x) = 1; exponents add when bases multiply log((x)(x9)) = 1 log(x^2 9x) = 1 10^log... = 10^1 x^2 9x = 10 x^2 9x 10 = 0 x= 10, 1 ; 1 is illegal to use in the equation becasue log(19) doesnt exist

radar
 5 years ago
Best ResponseYou've already chosen the best response.0adding as I did was really multiplying, and of course 10^x*10^x would equal 1.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.04.5 is illegal to use; becasue log(4.9) does not exist

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you can tell by graphing the log function and going over to 10 and 4.5 and looking around to find a y value.... it aint there :)

radar
 5 years ago
Best ResponseYou've already chosen the best response.0You have convinced me this problem is above my pay grade, please post the correct solution if you can or anyone can solve it.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the correct solution is: x = 10. And we all get lost in the math eventually ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you get that?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0........ if you scroll up and read the post, i actually typed it out a few times lol

radar
 5 years ago
Best ResponseYou've already chosen the best response.0wouldn't that result in 11=1 we know thats not right.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0log(109) + log(10) = 1 log(1) + 1 = 1 log(1) = 0 10^log(1) = 10^0 1 = 10^0 1 = 1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0also known as: 0 + 1 = 1

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Justme, did you see the flaw in the way I worked it? I hope I didn't mess you up. But the addition was illegal, as we were dealing with exponents, adding is exponents is the same as multiplying, and your problem was addition. I learned a lot on that thing!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0radar, me too that was the best lesson on log I have seen. thanks!
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