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anonymous

  • 5 years ago

Amistre64, still around?

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  1. amistre64
    • 5 years ago
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    ... is that a fat joke?...

  2. anonymous
    • 5 years ago
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    lol. I'm so glad to have you to lighten up the fact that calculus stinks! i have a piecewise function to type in here. Let me try to do it without the equation thingy,ok?

  3. amistre64
    • 5 years ago
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    . . . . . . *splat*

  4. anonymous
    • 5 years ago
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    -2x-3, x<or = to 2 -2x+5, x>2 Need to find where this is undefined. How?

  5. amistre64
    • 5 years ago
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    -2x-3, x </ 2 -2x+5, x > 2

  6. amistre64
    • 5 years ago
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    the y value is defined for all cases; there is a gap between the lines at x=2 but it is still defined there

  7. watchmath
    • 5 years ago
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    Let me write it down in more beautiful typesett :D \(\begin{cases}-2x-3&,x\leq 2\\-2x+5&,x>2\end{cases}\)

  8. amistre64
    • 5 years ago
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    maybe its asking for the missing gap?

  9. amistre64
    • 5 years ago
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    (-7,1) perhaps; do we have options?

  10. watchmath
    • 5 years ago
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    Maybe asking where the function is discontinuous.

  11. anonymous
    • 5 years ago
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    Ok, here's what it is asking for: To find where y' is undefined, find the value of x where the derivative on one side is different than the derivative on the other side. Does that make sense to you?

  12. anonymous
    • 5 years ago
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    Amistre64, are you still here?

  13. amistre64
    • 5 years ago
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    yes, english is my native tongue

  14. watchmath
    • 5 years ago
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    When the function is discontinuous at a point, then the derivative is undefined there/ So y' is undefined at x=2.

  15. amistre64
    • 5 years ago
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    the derivative of both side = -2

  16. amistre64
    • 5 years ago
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    the derivatives are never different, so I assume the answer is defined for all x

  17. amistre64
    • 5 years ago
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    y ' = -2 at x=2

  18. amistre64
    • 5 years ago
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    y = -2x+5 at x=2 its defined there by the domain (-inf,2]

  19. amistre64
    • 5 years ago
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    it jumps yes; but it is defined

  20. watchmath
    • 5 years ago
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    That is not correct amistre64. Remember that diffferentiability implies continuity.

  21. amistre64
    • 5 years ago
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    im reading up on that now :) but does "undefined" pertain to jumps? id like to verify your answer :)

  22. amistre64
    • 5 years ago
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    the limit from the left and the limit from the right of piecewise function may be different; so the limit of the function does not exists at x=2

  23. amistre64
    • 5 years ago
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    the limit exists from the left; and from the right; but the two are not the same...

  24. watchmath
    • 5 years ago
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    you can try to use the definition of derivative to check it.

  25. anonymous
    • 5 years ago
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    Thanks again! I'm sure I'll be back!

  26. amistre64
    • 5 years ago
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    i had to first figure out what the question was.. you did good watchmath :)

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