Amistre64, still around?

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Amistre64, still around?

Mathematics
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... is that a fat joke?...
lol. I'm so glad to have you to lighten up the fact that calculus stinks! i have a piecewise function to type in here. Let me try to do it without the equation thingy,ok?
. . . . . . *splat*

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Other answers:

-2x-3, x2 Need to find where this is undefined. How?
-2x-3, x 2
the y value is defined for all cases; there is a gap between the lines at x=2 but it is still defined there
Let me write it down in more beautiful typesett :D \(\begin{cases}-2x-3&,x\leq 2\\-2x+5&,x>2\end{cases}\)
maybe its asking for the missing gap?
(-7,1) perhaps; do we have options?
Maybe asking where the function is discontinuous.
Ok, here's what it is asking for: To find where y' is undefined, find the value of x where the derivative on one side is different than the derivative on the other side. Does that make sense to you?
Amistre64, are you still here?
yes, english is my native tongue
When the function is discontinuous at a point, then the derivative is undefined there/ So y' is undefined at x=2.
the derivative of both side = -2
the derivatives are never different, so I assume the answer is defined for all x
y ' = -2 at x=2
y = -2x+5 at x=2 its defined there by the domain (-inf,2]
it jumps yes; but it is defined
That is not correct amistre64. Remember that diffferentiability implies continuity.
im reading up on that now :) but does "undefined" pertain to jumps? id like to verify your answer :)
the limit from the left and the limit from the right of piecewise function may be different; so the limit of the function does not exists at x=2
the limit exists from the left; and from the right; but the two are not the same...
you can try to use the definition of derivative to check it.
Thanks again! I'm sure I'll be back!
i had to first figure out what the question was.. you did good watchmath :)

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