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anonymous

  • 5 years ago

can anyone help me with Exponential Growth?

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  1. amistre64
    • 5 years ago
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    can try

  2. anonymous
    • 5 years ago
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    A country's population in 1994 was 107 million. In 1997 it was 112 million. Estimate the population in 2008 using the exponential growth formula. Round your answer to the nearest million. \[P = Ae ^{kt}\]

  3. amistre64
    • 5 years ago
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    this is Population = inital size * e^(rate of change per year * years) right?

  4. anonymous
    • 5 years ago
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    i do believe so

  5. amistre64
    • 5 years ago
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    122 = 107.e^3r 122 ---- = e^3r 107 ln(122/107) = 3r r = 1/3 ln(122/107) = .04373... about 4.373 %

  6. amistre64
    • 5 years ago
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    P = 107.e(.04373(3)) = 121.999

  7. amistre64
    • 5 years ago
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    lol..... well thats right; now we just gotta adjust the time to 2008

  8. amistre64
    • 5 years ago
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    P = 107.e(.04373(14)) = 197.36....

  9. anonymous
    • 5 years ago
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    it says the answer is 132

  10. amistre64
    • 5 years ago
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    did i get my years wrong? 2008 1994 ----- 14 nope thats right...

  11. amistre64
    • 5 years ago
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    it could be a truncation error; i should try it with all the decimals then and see

  12. amistre64
    • 5 years ago
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    107 * (e^((1 / 3) * ln(122 / 107) * 14)) = 197.365857

  13. amistre64
    • 5 years ago
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    ahhhh i see what i did; i use 122..... the questions asks for 112

  14. amistre64
    • 5 years ago
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    yeah, i gotta learn to read :) 107 * (e^((1 / 3) * ln(112 / 107) * 14)) = 132.416952

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