## anonymous 5 years ago A farmer has 3 children and a herd of 30 cows. He gives 15 cows to his oldest child and 5 cows to his youngest child. Find the number os ways the farmer can split up his herd

1. anonymous

it's permutations and combinations we are on

2. watchmath

$${30 \choose 15}{15 \choose 5}=\frac{30!}{15!15!}\frac{15!}{10!5!}$$

3. anonymous

thanks so much

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