Amistre64, still there in the sky?

- anonymous

Amistre64, still there in the sky?

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- schrodinger

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- amistre64

whattup??

- anonymous

Need to combine piecewise functions. Here they are. Give me a sec.

- amistre64

with no money and no gas and no food; playing in here takes my mind off of the rest of that stuff :/

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## More answers

- anonymous

-(x-2), x<2
x-2, x>or=to 2 This is one piecewise.
-(x+6), x<6
x+6 x>or=to -6. This is the second part. Need to combine and simplify. How to do?

- anonymous

I know what you mean about no money, or gas and everything else! I am in the same boat in Illinois, but with nowhere near your brains! You one-upped me!

- anonymous

I'd rather be poor and starving and smart than poor starving and dumb!

- amistre64

:)

- amistre64

the 'or' means that the domain is a part of both sets

- amistre64

read it wrong :)
-(x-2) ; (-inf,1)
x-2; [2,inf) .......This is one piecewise.
...........................................
-(x+6) ; (-inf,6) <- is this a typo? maybe meant -6?
x+6 ; [-6,inf)

- amistre64

these are piecewise functions that define absolute value functions...

- anonymous

You know I forgot to type in the interval. Let me try to use the equation thing and type the whole thing, ok?

- amistre64

ok :)

- anonymous

Ok, I can'g even figure out the equation thing so here goes in long-hand style. : (

- anonymous

Apparetnly, I can't ype either. oops, I mean I can't type, either! Or spell!

- amistre64

the first piecewise combines and simplifies to:
f(x) = |x-2|
teh second one combines and simplifies to:
g(x) = |x+6|

- amistre64

does that help?

- anonymous

-(x-2), x<2
x-2, x>2
-(x+6), x<6
X+6, x>-6 Combine and simplify. The interval is -8

- anonymous

Ugh! Those are not right either!

- anonymous

Let me tell you that in both of those piecewise functions, the second "x is greater than" is supposed to be "greater than or equal to".

- anonymous

Did you hang up on me?

- amistre64

im here

- amistre64

do we have any options to determine if we are in the right ball park?

- anonymous

Do you want me to go back to MathXL and get the answer and give it to you so you know?

- amistre64

itd be helpful; because I got a notion that its gonna look like this:
f(x) =:
|x+6| ; [-8, y]
|x-3| ; [x,8]

- amistre64

well, the x, y stuff is from something else in me head lol

- anonymous

This is it, combined and simplified. BTW, I thought simplified was the shorter, easier version?!
-2x-4, -8

- amistre64

|x+6| ; [-8, n]
|x-3| ; [n,8]
n = where the graphs meet

- anonymous

Again, in the first inequality, it is supposed to be -8 is less than or equal to x is less than -6

- anonymous

The second line is supposed to be -6 is less than or equal to x is less than or equal to 2

- anonymous

The third line is supposed to be 2 is less than x is less than or equal to 8

- anonymous

Did you get all that or are you so sick of me you could scream?

- amistre64

right.... i got no idea how they did that tho :/

- amistre64

do you have a link to the material you are studying>?

- anonymous

I'm taking calc online with GCU and it's through MathXL, their math program. I don't know if I can send you a link. Let me check.

- anonymous

I cannot get a link and the problem shows that it takes 22 steps to figure it out! We are working with extrema with regards to where functions are undefined, where they equal zero, and then find the local min and max values.

- amistre64

i havent worked with piecewise functions in calculs yet; i heard they were out there, bit just havent seen that bear yet lol

- anonymous

I will try to get something online and send it. TTYSoon, Rachel. ps. you're awesome! Thanks for the time again. I'll be back!

- amistre64

youre welcome :)

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