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anonymous

  • 5 years ago

Amistre64, still there in the sky?

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  1. amistre64
    • 5 years ago
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    whattup??

  2. anonymous
    • 5 years ago
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    Need to combine piecewise functions. Here they are. Give me a sec.

  3. amistre64
    • 5 years ago
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    with no money and no gas and no food; playing in here takes my mind off of the rest of that stuff :/

  4. anonymous
    • 5 years ago
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    -(x-2), x<2 x-2, x>or=to 2 This is one piecewise. -(x+6), x<6 x+6 x>or=to -6. This is the second part. Need to combine and simplify. How to do?

  5. anonymous
    • 5 years ago
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    I know what you mean about no money, or gas and everything else! I am in the same boat in Illinois, but with nowhere near your brains! You one-upped me!

  6. anonymous
    • 5 years ago
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    I'd rather be poor and starving and smart than poor starving and dumb!

  7. amistre64
    • 5 years ago
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    :)

  8. amistre64
    • 5 years ago
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    the 'or' means that the domain is a part of both sets

  9. amistre64
    • 5 years ago
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    read it wrong :) -(x-2) ; (-inf,1) x-2; [2,inf) .......This is one piecewise. ........................................... -(x+6) ; (-inf,6) <- is this a typo? maybe meant -6? x+6 ; [-6,inf)

  10. amistre64
    • 5 years ago
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    these are piecewise functions that define absolute value functions...

  11. anonymous
    • 5 years ago
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    You know I forgot to type in the interval. Let me try to use the equation thing and type the whole thing, ok?

  12. amistre64
    • 5 years ago
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    ok :)

  13. anonymous
    • 5 years ago
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    Ok, I can'g even figure out the equation thing so here goes in long-hand style. : (

  14. anonymous
    • 5 years ago
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    Apparetnly, I can't ype either. oops, I mean I can't type, either! Or spell!

  15. amistre64
    • 5 years ago
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    the first piecewise combines and simplifies to: f(x) = |x-2| teh second one combines and simplifies to: g(x) = |x+6|

  16. amistre64
    • 5 years ago
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    does that help?

  17. anonymous
    • 5 years ago
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    -(x-2), x<2 x-2, x>2 -(x+6), x<6 X+6, x>-6 Combine and simplify. The interval is -8<x<8

  18. anonymous
    • 5 years ago
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    Ugh! Those are not right either!

  19. anonymous
    • 5 years ago
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    Let me tell you that in both of those piecewise functions, the second "x is greater than" is supposed to be "greater than or equal to".

  20. anonymous
    • 5 years ago
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    Did you hang up on me?

  21. amistre64
    • 5 years ago
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    im here

  22. amistre64
    • 5 years ago
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    do we have any options to determine if we are in the right ball park?

  23. anonymous
    • 5 years ago
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    Do you want me to go back to MathXL and get the answer and give it to you so you know?

  24. amistre64
    • 5 years ago
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    itd be helpful; because I got a notion that its gonna look like this: f(x) =: |x+6| ; [-8, y] |x-3| ; [x,8]

  25. amistre64
    • 5 years ago
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    well, the x, y stuff is from something else in me head lol

  26. anonymous
    • 5 years ago
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    This is it, combined and simplified. BTW, I thought simplified was the shorter, easier version?! -2x-4, -8<x<-6 8 -6<x<2 2x+4, 2<x<8

  27. amistre64
    • 5 years ago
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    |x+6| ; [-8, n] |x-3| ; [n,8] n = where the graphs meet

  28. anonymous
    • 5 years ago
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    Again, in the first inequality, it is supposed to be -8 is less than or equal to x is less than -6

  29. anonymous
    • 5 years ago
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    The second line is supposed to be -6 is less than or equal to x is less than or equal to 2

  30. anonymous
    • 5 years ago
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    The third line is supposed to be 2 is less than x is less than or equal to 8

  31. anonymous
    • 5 years ago
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    Did you get all that or are you so sick of me you could scream?

  32. amistre64
    • 5 years ago
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    right.... i got no idea how they did that tho :/

  33. amistre64
    • 5 years ago
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    do you have a link to the material you are studying>?

  34. anonymous
    • 5 years ago
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    I'm taking calc online with GCU and it's through MathXL, their math program. I don't know if I can send you a link. Let me check.

  35. anonymous
    • 5 years ago
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    I cannot get a link and the problem shows that it takes 22 steps to figure it out! We are working with extrema with regards to where functions are undefined, where they equal zero, and then find the local min and max values.

  36. amistre64
    • 5 years ago
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    i havent worked with piecewise functions in calculs yet; i heard they were out there, bit just havent seen that bear yet lol

  37. anonymous
    • 5 years ago
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    I will try to get something online and send it. TTYSoon, Rachel. ps. you're awesome! Thanks for the time again. I'll be back!

  38. amistre64
    • 5 years ago
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    youre welcome :)

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