The sum of three consecutive even integers is -24. Find the integers.

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The sum of three consecutive even integers is -24. Find the integers.

Mathematics
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The same idea spoyled. Why don't you give it a try first? :D
I dont understand this at all. Hoping to look at these and try to comprehend. These are all my practice exercises.
Ok, if the smallest number among the three is \(n\). Then the next even number is \(n+2\) and the next after that is \(n+2+2=n+4\). So the sum of these three even numbers is \(n+(n+2)+(n+4)=3n+6\) we want this sum to be equal to -24. So \(3n+6=-24\) \(3n=-30\) \(n=-10\) So the next two even numbers are -8, -6. Thus -10,-8,-6 are the answers.

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Les 2x = 1st integer 2x + 2 = 2nd 2x+4 = 3rd even integer the sum is -24 so 2x+2x+2+2x+4=-24 6x=-24-6=-30 x=-5 2x=-10 2x+2=-8 2x+4=-6 Making first digit equal 2x assures it is even. the next one is also even so it is 2x+2
thank you and that helps to understand process little better

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