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anonymous

  • 5 years ago

The sum of three consecutive even integers is -24. Find the integers.

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  1. watchmath
    • 5 years ago
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    The same idea spoyled. Why don't you give it a try first? :D

  2. anonymous
    • 5 years ago
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    I dont understand this at all. Hoping to look at these and try to comprehend. These are all my practice exercises.

  3. watchmath
    • 5 years ago
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    Ok, if the smallest number among the three is \(n\). Then the next even number is \(n+2\) and the next after that is \(n+2+2=n+4\). So the sum of these three even numbers is \(n+(n+2)+(n+4)=3n+6\) we want this sum to be equal to -24. So \(3n+6=-24\) \(3n=-30\) \(n=-10\) So the next two even numbers are -8, -6. Thus -10,-8,-6 are the answers.

  4. radar
    • 5 years ago
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    Les 2x = 1st integer 2x + 2 = 2nd 2x+4 = 3rd even integer the sum is -24 so 2x+2x+2+2x+4=-24 6x=-24-6=-30 x=-5 2x=-10 2x+2=-8 2x+4=-6 Making first digit equal 2x assures it is even. the next one is also even so it is 2x+2

  5. anonymous
    • 5 years ago
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    thank you and that helps to understand process little better

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