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anonymous

  • 5 years ago

factor the polynomial and check your answer 4m^4 - 2m^2 + 8m

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  1. shadowfiend
    • 5 years ago
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    Is there a common power of m in all three of those terms?

  2. anonymous
    • 5 years ago
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    nope

  3. shadowfiend
    • 5 years ago
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    There is. Remember that \(m^4 = m \cdot m \cdot m \cdot m\) and \(m^2 = m \cdot m\).

  4. anonymous
    • 5 years ago
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    what?

  5. shadowfiend
    • 5 years ago
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    \[4m^4 - 2m^2 + 8m = 4mmmm - 2mm + 8m\] So you can pull a single m out of all three terms: \[m(4m^3 - 2m + 8)\] There's one more common factor, it's a number though. Is there a factor common to 4, 2, and 8?

  6. anonymous
    • 5 years ago
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    2?

  7. anonymous
    • 5 years ago
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    ?

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