anonymous
  • anonymous
A country's population in 1995 was 228 million. In 2001 it was 230 million. Estimate the population in 2010 using the exponential growth formula. Round your answer to the nearest million
Mathematics
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anonymous
  • anonymous
A country's population in 1995 was 228 million. In 2001 it was 230 million. Estimate the population in 2010 using the exponential growth formula. Round your answer to the nearest million
Mathematics
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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dumbcow
  • dumbcow
\[P _{t}=P _{0}e ^{kt}\] Find k \[230 = 228*e ^{6k}\] \[k = \frac{\ln 230/228}{6}\] Substitute this value in to find P15 2010-1995 = 15 \[P _{15}=228*e ^{15*\ln (230/228)/6}\]
anonymous
  • anonymous
can you solve it for me? i'm not sure how to
dumbcow
  • dumbcow
i did solve it just calculate P15 using a calculator

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anonymous
  • anonymous
how do i do that?
dumbcow
  • dumbcow
ok can you find ln(230/228) ?
anonymous
  • anonymous
not sure
dumbcow
  • dumbcow
press the ln button and then "(230/228)" did you understand any of the steps i did?
anonymous
  • anonymous
i got 0.008733 from the In 230/228. then what??????????????????
anonymous
  • anonymous
They Answer to that is 232. Youre welcome

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