anonymous
  • anonymous
How many different three-letter arrangements can be formed using the letters in the word ABSOLUTE if each letter is used only once? A. 56 B. 112 C. 168 D. 336
Mathematics
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anonymous
  • anonymous
How many different three-letter arrangements can be formed using the letters in the word ABSOLUTE if each letter is used only once? A. 56 B. 112 C. 168 D. 336
Mathematics
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
Woo!! last question!! ^^
watchmath
  • watchmath
There are 8 letters and we want to choose 3 among them. So 8 choose 3, i.e \(\frac{8!}{5!3!}=\frac{6\times 7\times 8}{1\times 2\times 3}=56\)
anonymous
  • anonymous
simplify the expression: (√7+√385)(√55+√11)

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anonymous
  • anonymous
Ohhhh okie dokie (: Thanks a but load

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