## anonymous 5 years ago How many different three-letter arrangements can be formed using the letters in the word ABSOLUTE if each letter is used only once? A. 56 B. 112 C. 168 D. 336

1. anonymous

Woo!! last question!! ^^

2. watchmath

There are 8 letters and we want to choose 3 among them. So 8 choose 3, i.e $$\frac{8!}{5!3!}=\frac{6\times 7\times 8}{1\times 2\times 3}=56$$

3. anonymous

simplify the expression: (√7+√385)(√55+√11)

4. anonymous

Ohhhh okie dokie (: Thanks a but load