## anonymous 5 years ago What is the inverse of log (base 3) 2x?

Let $$y=\log_3(2x)$$ Then $$3^y=2x$$ $$x=\frac{1}{2}\cdot 3^y$$ Switch between $$x$$ and $$y$$ we have $$y=\frac{1}{2}\cdot 3^x$$ as the inverse function.