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anonymous
 5 years ago
what are the real or imaginary solutions of the polynomial equation 125x^3 + 343 = 0
anonymous
 5 years ago
what are the real or imaginary solutions of the polynomial equation 125x^3 + 343 = 0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0factor the sum of two cubes.

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0\((5x)^3+9^3=0\) \((5x)^3=9^3\) \(5x=9\) \(x=9/5\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(5x^3)+7^3=(5x+7)((5x)^25x\times 7 + 7^2)\]

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0oh I forgot the imaginary ...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and cube root of 343 is 7 not 9 i think

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0yes :) you were right sattelite. So ignore my answer :D.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am using \[a^3+b^3=(a+b)(a^2ab+b^2)\]

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0we need two more complex solutions dumbcow

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so we have \[(5x+7)(25x^235x+49)=0\] \[5x+7=0\] \[x=\frac{7}{5}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and the other two you find using the quadratic formula.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i will write them out if you like

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{35\pm \sqrt{35^24\times 25\times 49}}{2\times 25}\] \[\frac{35\pm \sqrt{3675}}{50}\] \[\frac{35\pm 5\sqrt{147}i}{50}\] \[\frac{7\pm \sqrt{147}i}{10}\]
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