## anonymous 5 years ago How do I find the value of Sigma n=1 to infinity n/k^n (k>1)

1. anonymous

n = 1 to infinity or k = 1 to infinity?

2. anonymous

$\sum_{1}^{\infty} n/k ^{2}$ n=1 to infinity... k>1

3. anonymous

i am confused because for fixed k this sum does not converge. for example if k = 1 you get $\Sigma_1^\infty n$ which is infinite

4. anonymous

It's supposed to be solved using the results of the 1st question I asked involving showing the $\sum_{1}^{\infty} n x ^{n} = f(x) x/(1-x)^2$