## anonymous 5 years ago Solve: sec²θ = 2tanθ+4 over the interval [0,2pi)

1. anonymous

$\sec ^{2}\Theta=1+\tan ^{2}\theta$ substitute & solve it as quadratic equation for tan

2. anonymous

i got as far as (x+1)(x-3) =tan²=-1 and tan²=3 but I don't know what to do next?