• anonymous
Help With Problem 1a initial=1 Denom=3 OddPrime=True PrimeNumber=0 if (Denom/2)*2==Denom: OddPrime=False print 'Number is even.' else: OddPrime=True print 'Number is odd, checking if prime..' if OddPrime==True: while PrimeNumber<1001: for i in range(initial,Denom): if Denom%i==0: OddPrime=False if OddPrime==False: Denom+=2 else: OddPrime=True if OddPrime==True: Denom+=2 PrimeNumber+=1 if PrimeNumber==1000
MIT 6.00 Intro Computer Science (OCW)
• Stacey Warren - Expert brainly.com
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SOLVED
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