anonymous
  • anonymous
Help plz 1) Find the equation of the line in point-slope form containing the point (-4,7) and parallel to the line 3x-5y=9
Mathematics
chestercat
  • chestercat
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saifoo.khan
  • saifoo.khan
hey! its easy!
anonymous
  • anonymous
1) present given equation in form : y=... 5y=3x-9 y=3/5 *x - 9/5 2) you found that the slope of given line is 3/5 your line = parallel to the give line, so - the same slope; 3) equation of the line containing point (-4,7): y-7=(3/5) *(x- (-4)) y=(3/5)x +(12/5) +7 y=(3/5)x + 47/5
saifoo.khan
  • saifoo.khan
YeaH! Correct. i was just about to type it. :)

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anonymous
  • anonymous
is this all its asking? cuz i got that answer too but i wasnt sure if it was finished
saifoo.khan
  • saifoo.khan
it fine. If i had to write it thn, i would hav written: 5y=3x +47.
anonymous
  • anonymous
Ok, but what if its a perpendicular line instead of a parallel line?
anonymous
  • anonymous
use the reciprocal correct? which would be instead of 3/5 => -5/3?
saifoo.khan
  • saifoo.khan
thn v'll apply the formuale: m1 x m2 = -1 Yeah! crrect,
anonymous
  • anonymous
so answer would be y = (-5/3)x +(1/3)
saifoo.khan
  • saifoo.khan
there should a cordinate through which u may find wht is the cordinate?
anonymous
  • anonymous
um you mean the points its containing? its "...containing the point (-4,7) and perpendicular to the line 3x-5y=9"
saifoo.khan
  • saifoo.khan
oh! thn the gradient of this line will b 1/3.
saifoo.khan
  • saifoo.khan
thn u may add the value of y-intercept which u may find with a cordinate & the gradient 1/3
anonymous
  • anonymous
i dont understand, what do u mean?
saifoo.khan
  • saifoo.khan
till where u understood?
anonymous
  • anonymous
i got the answer of \[y = (-5 \ 3)x + (1 \ 3)\] <
anonymous
  • anonymous
weird... those two are fractions* -5/3 and 1/3
saifoo.khan
  • saifoo.khan
this is the main line on which there is a perpendicular?
anonymous
  • anonymous
i believe so, thats what i solved for using the point slope formula. and i got the slope from the problem i had done above with the parallel line
saifoo.khan
  • saifoo.khan
sorry man! i gotta go now. tc. :)

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