At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
hey! its easy!
1) present given equation in form : y=... 5y=3x-9 y=3/5 *x - 9/5 2) you found that the slope of given line is 3/5 your line = parallel to the give line, so - the same slope; 3) equation of the line containing point (-4,7): y-7=(3/5) *(x- (-4)) y=(3/5)x +(12/5) +7 y=(3/5)x + 47/5
YeaH! Correct. i was just about to type it. :)
is this all its asking? cuz i got that answer too but i wasnt sure if it was finished
it fine. If i had to write it thn, i would hav written: 5y=3x +47.
Ok, but what if its a perpendicular line instead of a parallel line?
use the reciprocal correct? which would be instead of 3/5 => -5/3?
thn v'll apply the formuale: m1 x m2 = -1 Yeah! crrect,
so answer would be y = (-5/3)x +(1/3)
there should a cordinate through which u may find wht is the cordinate?
um you mean the points its containing? its "...containing the point (-4,7) and perpendicular to the line 3x-5y=9"
oh! thn the gradient of this line will b 1/3.
thn u may add the value of y-intercept which u may find with a cordinate & the gradient 1/3
i dont understand, what do u mean?
till where u understood?
i got the answer of \[y = (-5 \ 3)x + (1 \ 3)\] <
weird... those two are fractions* -5/3 and 1/3
this is the main line on which there is a perpendicular?
i believe so, thats what i solved for using the point slope formula. and i got the slope from the problem i had done above with the parallel line
sorry man! i gotta go now. tc. :)