anonymous
  • anonymous
Rationalize and Simplify 5i - 2i ----- 1 - 2i
Mathematics
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anonymous
  • anonymous
Rationalize and Simplify 5i - 2i ----- 1 - 2i
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
multiply by 1+2i to realize the denominator you then get (3i - 6)/5
anonymous
  • anonymous
wait what??can you explain?
anonymous
  • anonymous
Your numerator = 5i -2i = 3i Now, your denominator has to be free of all i's. How do we cancel out the i in the denominator? We multiply 1-2i by 1+2i (but to be valid, we need to multiply the top by 1+2i as well) 3i(1+2i) = 3i +6i^2 = 3i - 6 (1+2i)(1-2i) = 1 -4i^2 = 1+4 = 5 3i-6/5

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