anonymous
  • anonymous
It takes Jake 9 hours longer than Joe to rebuild an engine. Working together, they can do the job in 20 hours. How long would it take each, working alone, to rebuild an engine?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
take it suzi
anonymous
  • anonymous
9 = 3^2 20 = 2^2 * 5 3^2 * 2^2 * 5 180 hours?
anonymous
  • anonymous
jake does it in x hours. Therefore, his rate is 1/x Joe does it in y hours. Therefore, his rate is 1/y 20/y+20/x = 1 y+9 = x 20/y + 20/(y+9) = 1 40y+180= y^2 +9y y^2 -31y +180 = 0 then use the quadratic formula :D

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