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anonymous

  • 5 years ago

Help please... I'm terrible at math can someone tell me the value of X and how to find it? This is the problem 5^(x-1)=2^x

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  1. anonymous
    • 5 years ago
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    \[5^{x-1}=2^x\] take log of both side \[\log 5^{x-1}=\log 2^x\] pull out the exponent \[{x-1}\log 5=xlog 2\]

  2. anonymous
    • 5 years ago
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    xlog 5 -log5=xlog2 xlog 5-xlog2=log5

  3. anonymous
    • 5 years ago
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    x(log 5 - log 2)=log 5

  4. anonymous
    • 5 years ago
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    Thank you so much... but... what is X?

  5. anonymous
    • 5 years ago
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    divide both side by (log 5- log 2) then you would have x by itself

  6. anonymous
    • 5 years ago
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    Oh wow! Thanks! I totally love you!

  7. anonymous
    • 5 years ago
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    then you may award me a medal or fan me

  8. anonymous
    • 5 years ago
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    How do I do that? This is literally my first time...

  9. shadowfiend
    • 5 years ago
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    Click good answer on the right of their answer :) You can hover over their avatar to become a fan!

  10. anonymous
    • 5 years ago
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    thanks to both of you!

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spraguer (Moderator)
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