anonymous
  • anonymous
Help please... I'm terrible at math can someone tell me the value of X and how to find it? This is the problem 5^(x-1)=2^x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[5^{x-1}=2^x\] take log of both side \[\log 5^{x-1}=\log 2^x\] pull out the exponent \[{x-1}\log 5=xlog 2\]
anonymous
  • anonymous
xlog 5 -log5=xlog2 xlog 5-xlog2=log5
anonymous
  • anonymous
x(log 5 - log 2)=log 5

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anonymous
  • anonymous
Thank you so much... but... what is X?
anonymous
  • anonymous
divide both side by (log 5- log 2) then you would have x by itself
anonymous
  • anonymous
Oh wow! Thanks! I totally love you!
anonymous
  • anonymous
then you may award me a medal or fan me
anonymous
  • anonymous
How do I do that? This is literally my first time...
shadowfiend
  • shadowfiend
Click good answer on the right of their answer :) You can hover over their avatar to become a fan!
anonymous
  • anonymous
thanks to both of you!

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