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anonymous
 5 years ago
Help please... I'm terrible at math can someone tell me the value of X and how to find it? This is the problem 5^(x1)=2^x
anonymous
 5 years ago
Help please... I'm terrible at math can someone tell me the value of X and how to find it? This is the problem 5^(x1)=2^x

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[5^{x1}=2^x\] take log of both side \[\log 5^{x1}=\log 2^x\] pull out the exponent \[{x1}\log 5=xlog 2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0xlog 5 log5=xlog2 xlog 5xlog2=log5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x(log 5  log 2)=log 5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank you so much... but... what is X?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0divide both side by (log 5 log 2) then you would have x by itself

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh wow! Thanks! I totally love you!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you may award me a medal or fan me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How do I do that? This is literally my first time...

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Click good answer on the right of their answer :) You can hover over their avatar to become a fan!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks to both of you!
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