anonymous
  • anonymous
Help please... I'm terrible at math can someone tell me the value of X and how to find it? This is the problem 5^(x-1)=2^x
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
\[5^{x-1}=2^x\] take log of both side \[\log 5^{x-1}=\log 2^x\] pull out the exponent \[{x-1}\log 5=xlog 2\]
anonymous
  • anonymous
xlog 5 -log5=xlog2 xlog 5-xlog2=log5
anonymous
  • anonymous
x(log 5 - log 2)=log 5

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Thank you so much... but... what is X?
anonymous
  • anonymous
divide both side by (log 5- log 2) then you would have x by itself
anonymous
  • anonymous
Oh wow! Thanks! I totally love you!
anonymous
  • anonymous
then you may award me a medal or fan me
anonymous
  • anonymous
How do I do that? This is literally my first time...
shadowfiend
  • shadowfiend
Click good answer on the right of their answer :) You can hover over their avatar to become a fan!
anonymous
  • anonymous
thanks to both of you!

Looking for something else?

Not the answer you are looking for? Search for more explanations.