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anonymous

  • 5 years ago

i have just a couple more questions as I am trying to teach myself the steps to figure these , i want to write an equation of a line that passes through point(2,5) and has a slope of 3.

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  1. anonymous
    • 5 years ago
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    okay, there are two nice equations to know for solving an equation of a line Point slope: y-b = m (x-a) Slope-intercept Form: y=mx +b For both you need the slope and a point the equation needs to pass through. For point slope, if you have slope 3 and Point A = (a,b) (or in your case (2,5)) y-5 = 3(x-2) In slope-intercept form, you plug in values of y & x to get b y=3x +b 5 = 6 +b b=-1 y= 3x -1

  2. anonymous
    • 5 years ago
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    So Y=Mx+b is the normal equation of a line... so then just add 3 over 1 so it would be y=3over1x

  3. anonymous
    • 5 years ago
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    don't i have to go any further once i came to y=3x-1?

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