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M
 5 years ago
x is exponential random variable
f(x) = (1/θ)e^x/θ
given: P(x < 2.40) = .520
find: P(x > 4.36)
M
 5 years ago
x is exponential random variable f(x) = (1/θ)e^x/θ given: P(x < 2.40) = .520 find: P(x > 4.36)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You need to integrate f(x) from 0 to 2.40 and set that equal to .520. You will have an equation you can solve for theta. Once you find theta integrate the pdf again from 4.36 to infinity, or take one minus the integration from 0 to 4.36 whichever you prefer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry i dont know why it posted that many times

M
 5 years ago
Best ResponseYou've already chosen the best response.0i keep getting a negative number for the theta 1.5694 i end up with a negative answer which i don't think it's correct

M
 5 years ago
Best ResponseYou've already chosen the best response.0e^2.40/theta  [e^0/theta] = .520 e^2.40/theta + 1 = .520 e^2.40/theta = .48 2.40/theta = ln(.48) theta = 3.2699 i was trying to ln the limit 0 at first and that's why i was having problem. yay for perseverance :)

M
 5 years ago
Best ResponseYou've already chosen the best response.0e^2.40/theta  [e^0/theta] = .520 e^2.40/theta + 1 = .520 e^2.40/theta = .48 2.40/theta = ln(.48) theta = 3.2699 ex/theta from 4.36 to infinity e^inf/3.269  [e^4.36/3.269] = 0 + .2635 =.2635

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yep I think that's correct
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