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anonymous

  • 5 years ago

You attach a powerful spring to a high ceiling 10 meters above you. You attach a waterballoon filled with about 10 liters of cold delicious Tiger Beer to the end of the spring. After the balloon is attached the spring hangs down 5 meters. Now you stretch the spring manually to the floor. Write a differential equation describing the motion of the balloon up until it hits the ceiling. You can assume the damping force due to air resistance is minus 2 times the speed of the balloon. Solve your differential equation. Also, why in the world would you do this? I mean the beer shower would be pretty a

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  1. anonymous
    • 5 years ago
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    Do you want the answer or not? Or is this just a joke?

  2. anonymous
    • 5 years ago
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    the answer

  3. anonymous
    • 5 years ago
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    okay: Friction= -2v Restoring force = kx Gravity = -mg Fnet = ma ma = kx - mg -2v m(d^2x/dt^2) = kx - mg - 2 (dx/dt)

  4. anonymous
    • 5 years ago
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    \[m(d ^{2}x/dt ^{2}) = kx - mg - 2(dx/dt)\]

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