You have a 3-card deck containing a king, a queen, and a jack. You draw a random card, then put it back and draw a second random card. Calculate the probability that you draw exactly 1 king.

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Same as the earlier question about the jack: 2/3*1/2 = 1/3

P(draw both jacks) = 1/3*1/3 = 1/9
P(no jacks) = 2/3*2/3 = 4/9
P(1 jack) = 1 - 1/9 - 4/9 = 4/9

its different because there is replacement

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