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anonymous
 5 years ago
e^log3  e^log 2 =
anonymous
 5 years ago
e^log3  e^log 2 =

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1thats assuming thats log base e

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh i see is it the same as doing this e^log3  e^log 2 = e^log1 =e^0 =1

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1e^x and lnx are inverse functions so e^ln3=3 and e^ln2=2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh so they cancel out

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1yea! are we to assume that the logs are base e?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes it says it in the text book also one other question \[\int\limits_{\log6}^{\log4} e ^{x}\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1the antiderivative of e^(x) is e^(x)+C

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what ive done is this [\[[e^{x}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you get e^log6+e^log4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then using what you said before the answer should be 10

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1no upper limit is log4 right? lower limit is log6 right? it looks like you plugged in the lower limit first

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1and also if we simplify what you have we have 6^(1)+4^(1)=......

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{\log4}^{\log6}e ^{x}\] it should be that lol sorry i did it the wrong way round.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1ok then what you have is right but you still simplified wrong

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1do you remember rlogx=logx^r

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah my answer is wrong according to the back of the book the answer should be 1/12

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1so we have e^[log6]=e^log6^(1)=6^(1)=1/6 and we have e^[log4]=e^log4^(1)=4^(1)=1/4

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1and, you still there?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1do you got it from here? i'm fixing to go to bed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok yeah thanks i get it lol thanks :) good night
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