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anonymous
 5 years ago
hi all
anonymous
 5 years ago
hi all

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I need some help with some math :/

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If sin theta = 8/9, 0<theta<Pi/2, find the exact value of each of the following. sin2theta

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin^2theta+cos^2theta=1 we know tht sin theta = 8/9, therefore sin^2theta = 64/81 by re arrnging we get cos^2theta = 1  64/81 cos^2 theta = 17/81 cos theta = sqrt(17)/9 sin2theta=2sin theta x cos theta =2sin(8/9)x cos(sqrt(17)/9)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is there a times between x and cos?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0correct answer was 16sqrt17/81 :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but i get another shot

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If sin(theta)=1/6, 0<(theta)<Pi/2, find the exact value for each of the following. sin(2theta)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah thats the answer sintheta = 8/9 cos theta=sqrt(17)/9 2(8/9) x sqrt(17)/9 =16sqrt17/81
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