hi all

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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I need some help with some math :/
If sin theta = 8/9, 0
sin^2theta+cos^2theta=1 we know tht sin theta = 8/9, therefore sin^2theta = 64/81 by re arrnging we get cos^2theta = 1 - 64/81 cos^2 theta = 17/81 cos theta = sqrt(17)/9 sin2theta=2sin theta x cos theta =2sin(8/9)x cos(sqrt(17)/9)

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Other answers:

is there a times between x and cos?
yeah it is a times
correct answer was 16sqrt17/81 :(
but i get another shot
If sin(theta)=1/6, 0<(theta)
yeah thats the answer sintheta = 8/9 cos theta=sqrt(17)/9 2(8/9) x sqrt(17)/9 =16sqrt17/81

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