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anonymous

  • 5 years ago

hi all

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  1. anonymous
    • 5 years ago
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    I need some help with some math :/

  2. anonymous
    • 5 years ago
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    If sin theta = 8/9, 0<theta<Pi/2, find the exact value of each of the following. sin2theta

  3. anonymous
    • 5 years ago
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    sin^2theta+cos^2theta=1 we know tht sin theta = 8/9, therefore sin^2theta = 64/81 by re arrnging we get cos^2theta = 1 - 64/81 cos^2 theta = 17/81 cos theta = sqrt(17)/9 sin2theta=2sin theta x cos theta =2sin(8/9)x cos(sqrt(17)/9)

  4. anonymous
    • 5 years ago
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    is there a times between x and cos?

  5. anonymous
    • 5 years ago
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    yeah it is a times

  6. anonymous
    • 5 years ago
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    correct answer was 16sqrt17/81 :(

  7. anonymous
    • 5 years ago
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    but i get another shot

  8. anonymous
    • 5 years ago
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    If sin(theta)=1/6, 0<(theta)<Pi/2, find the exact value for each of the following. sin(2theta)

  9. anonymous
    • 5 years ago
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    yeah thats the answer sintheta = 8/9 cos theta=sqrt(17)/9 2(8/9) x sqrt(17)/9 =16sqrt17/81

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